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4x^2-35x+36=-8x+1
We move all terms to the left:
4x^2-35x+36-(-8x+1)=0
We get rid of parentheses
4x^2-35x+8x-1+36=0
We add all the numbers together, and all the variables
4x^2-27x+35=0
a = 4; b = -27; c = +35;
Δ = b2-4ac
Δ = -272-4·4·35
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-13}{2*4}=\frac{14}{8} =1+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+13}{2*4}=\frac{40}{8} =5 $
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